This circuits can help begginers to understand a transistor and use it for their ciruits. i will explain the general working of the transistor as a swithch and finally will give you few ideas of how all i used it.
Binary Output with a transistor:
1) Design a circut which allows a PIC processor to drive an LED array. This LED array has the following properties:
Vf @ 80mA = 10.2V ( six red LEDs are placed in series, giving 6 x 1.7V = 10.2V)
Assume that the PIC is only capable of driving 10mA at 5V.
Step 1. Find a transistor which can withstand 80mA.
110 < hFE < 450 ——>meaning you can count on a gain of atelast 300
max IC (Sat) = 200mA ——>meaning this can take 200mA. 80mA is quite small rite.
VCE(Sat) = 0.25V ——>a rough estimate of VCE at saturation
VCEO = 45V ——->meaning this transistor can take +45V when turned off
Step 2: Find a power supply bigger than 10.2V. Arbitrarilly assume a +24 supply.
Step 3: Find Rc to limit the current to 80mA
RC =( 24V-10.2V-0.25V)/ 80mA = 170 ohms
Step 4: Find RB to saturate the transistor. At the lowest gain, to put you just at the point of saturation,
Ib = ICE/hfe = 80mA /150 = 534uA —->150 is typical Hfe for BC107B in datasheet*
RB = 5V-0.7V/534uA = 32kohm
Pick R smaller than this to assure you saturate this stage. Let R = 10k.
In this pic that i got from a random site kindly overlook the ZTX1051A transistor with Hfe>300. i have shown you calculations for BC107.
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2) Design a circuit whichuses a single output from the PIC processor, and allows a PIC processor to drive this motor in the clockwise direction at either 0% speed (0V) or 100% speed (+5V). Assume the motor draws 470mA at +5V.
Step 1: Pick a transistor. I'll stick with a BC107 because I like this transistor.
Step 2: Add the motor to the collector. You don't need a current limiting resistor since the motor's armature resistance and back EMF limit the current to 470mA @ 5V.
Step 3: Add RB to saturate the transistor. Worst case, when the gain is minimum (300) and you're just at the point of saturation:
IB = ICE/Hfe = 470mA/150 = 3.14mA
RB = 5V-0.7V/3.14mA = 5.48kohm
Step 4: Just to make sure that you saturate the transistor, make Rb smaller than this. Let RB = 2k.note: The inductance in the motor stores energy in a magnetic field. When the current is turned off (the transistor turns off) the energy in the field has to go somewhere. To save the transistor, place a diode across the motor to allow the collapsing field to drive current through the diode – saving the transistor
again the ZTX1051A is replaced by BC107 and the current at 2k at base resistance is 3.14mA.
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3) Design a circuit which can drive the motor forward and in reverse using transistors:This is the transistor version of my ULN2003 H-Bridge
You can use the same circuit as before, only add another NPN and two more PNP transistors. The equations work out
the same for each transistor:
NPN:BC107
OFF: put the input to 0V. This assures that 0A flow through the diode.
ON: make RB = 2k to saturate this transistor when 470mA flow though it.
IB > 470mA/Hfe = 3.14mA
RB < 5V-0.7V/1.57mA = 5.48kohm
Let RB = 2k.
PNP: BC177(since I picked a transistor with the same gain (Hfe or b)
OFF: put the input to +5V. This assures there is no potential across the base diode and no current flows.
ON: Make RB = 2k to saturate this transistor when 470mA flows through it.
IB > 470mA/Hfe = 3.14mA
RB < 5V-0.7V/3.14mA =5.48k
Let RB = 2k

That will do…..
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MY IDEAS TO USE TRANSISTORS AS SWITCH:
1) I connected my local FM radio reciever to my parallel port. There are only two switches to operate it. one for selecting channel and the other for reset . just connect it this way below and you can write a code in VB or C to address the ports and to scan or reset.

The two black thigs are the switches.. just pic the two sides which the switch shorts on pressing and make this combination and get your electronic switch working.
2) I have connected my calculator and microcontroller using the same concep.. I will put those pics later as my friend is havin the digi as of now!!
Cheers trying the circuits. Keep giving your coments plas (it will cheer me up!!) –Madan